![]() ![]() Local regen = false - determines whether PIN will regenerate after a failed attempt Then, use the following LocalScript placed inside the PIN frame: - Script settings If someone could assist me on how to do this, I would appreciate it greatlyįirst, download this and put it in a ScreenGui in StarterGui. It's mainly because of my lack of experience in LUA, I'm more advanced in Python and barely know a thing in Java. I've literally tried everything I could but nothing. The Player would first have to enter an "initial" number, meaning in order to enter the randomly generated number he first needed to input the static pin in order to "log in," after that, then he would try to guess the number. Anyway, I needed to create a keypad using SurfaceGUI, and display it on a separate screen, as a typical keypad would. no, it needs to be SurfaceGUI, which I don't know how to handle well. I need to create a game in which I have to create a keypad of sorts, at first I thought GUI would work. Luckily not the parts and models, otherwise I'm really screwed. at the end, I let frustration take control of me and I ended up deleting the whole script. my code didn't work the first time, the second time, the third time. I have tried everything (based on the knowledge I know) and yet nothing. So, I've been working on this for the past week.
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